The relationship between the magnetic susceptibility $ \chi $ and the magnetic permeability $ \mu $ is given by:
$ \mu_0 $ is the permeability of free space and $ \mu_r $ is relative permeability.
The problem asks for the correct relationship between magnetic susceptibility (\(\chi\)) and magnetic permeability (\(\mu\)), also involving the permeability of free space (\(\mu_0\)) and relative permeability (\(\mu_r\)).
The solution is derived from the fundamental definitions of magnetic quantities.
Step 1: Start with the fundamental relationship between \( \vec{B} \), \( \vec{H} \), and \( \vec{M} \).
\[ \vec{B} = \mu_0 (\vec{H} + \vec{M}) \]
Step 2: Substitute the definition of magnetic susceptibility (\( \vec{M} = \chi \vec{H} \)) into the equation from Step 1.
\[ \vec{B} = \mu_0 (\vec{H} + \chi \vec{H}) \]
Step 3: Factor out the magnetic field strength \( \vec{H} \) from the expression.
\[ \vec{B} = \mu_0 (1 + \chi) \vec{H} \]
Step 4: Use the definition of magnetic permeability (\( \vec{B} = \mu \vec{H} \)) to relate \( \mu \) and \( \chi \).
By comparing the equation from Step 3 with \( \vec{B} = \mu \vec{H} \), we can equate the expressions for \( \vec{B} \):
\[ \mu \vec{H} = \mu_0 (1 + \chi) \vec{H} \]
Canceling \( \vec{H} \) from both sides, we get the relationship between \( \mu \), \( \mu_0 \), and \( \chi \):
\[ \mu = \mu_0 (1 + \chi) \]
Step 5: Rearrange the equation to express \( \chi \) in terms of \( \mu \) and \( \mu_0 \).
Divide both sides of the equation by \( \mu_0 \):
\[ \frac{\mu}{\mu_0} = 1 + \chi \]
Now, solve for \( \chi \):
\[ \chi = \frac{\mu}{\mu_0} - 1 \]
We can also express this using the definition of relative permeability, \( \mu_r = \frac{\mu}{\mu_0} \):
\[ \chi = \mu_r - 1 \]
Comparing our derived result with the given options, the correct relationship is:
\( \chi = \frac{\mu}{\mu_0} - 1 \)

An infinitely long straight wire carrying current $I$ is bent in a planar shape as shown in the diagram. The radius of the circular part is $r$. The magnetic field at the centre $O$ of the circular loop is :


Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : If oxygen ion (O\(^{-2}\)) and Hydrogen ion (H\(^{+}\)) enter normal to the magnetic field with equal momentum, then the path of O\(^{-2}\) ion has a smaller curvature than that of H\(^{+}\).
Reason R : A proton with same linear momentum as an electron will form a path of smaller radius of curvature on entering a uniform magnetic field perpendicularly.
In the light of the above statements, choose the correct answer from the options given below

Foot of perpendicular from origin on a line passing through $(1, 1, 1)$ having direction ratios $\langle 2, 3, 4 \rangle$, is:
A line through $(1, 1, 1)$ and perpendicular to both $\hat{i} + 2\hat{j} + 2\hat{k}$ and $2\hat{i} + 2\hat{j} + \hat{k}$, let $(a, b, c)$ be foot of perpendicular from origin then $34 (a + b + c)$ is: