Question

The products obtained when chlorine gas reacts with cold and dilute aqueous $NaOH$ are:

• (A) $C{l}^{-}$ and $Cl{O}^{-}$
• (B) $C{l}^{-}$ and $Cl{O}_2^{-}$
• (C) $C{l}^{-}$ and $Cl{O}_3^{-}$
• (D) $C{l}^{-}$ and $Cl{O}_4^{-}$

Answer 1

The Correct Option is A

Explanation:
The reaction between chlorine and cold dilute sodium hydroxide solution is: $NaCl{O}_3$ is sodium chlorate(I). The old name for this is sodium hypochlorite. Actually, the product depends upon the fact whether $NaOH$ used was dilute and cold/concentrated and hot. If Chlorine reacts with cold $NaOH$, it gives $NaCl$ & $NaOCl$.$\Rightarrow C{l}^{-}$ and $Cl{O}^{-}$Hence, the correct option is (A).