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The points on the curve \(\frac{x^2}{9} + \frac{y^2}{16} = 1\) at which the tangents are parallel to x-axis:
The points on the curve \(\frac{x^2}{9} + \frac{y^2}{16} = 1\) at which the tangents are parallel to x-axis:
Updated On: May 18, 2024
- (0,4), (0,-4)
- (0, 0), (0,-4)
- (4, 0), (-4, 0)
- (0, 0), (0, 4)
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The Correct Option is A
Solution and Explanation
The correct option is (A): (0,4), (0,-4)
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