Question

The pair of quantities having same dimensions is

• A. Impulse and Surface Tension
• B. Angular momentum and Work
• C. Work and Torque
• D. Young's modulus and Energy

Answer 1

The Correct Option is C

Impulse = Force $\times$ time
$=[MLT^{-2}][T]$
$=[MLT^{-1}]$

Surface tension$=\frac{\text{Force}}{\text{length}}$
$=\frac{[MLT^{-2}]}{[L]}$
$=[ML^0T^{-2}]$
Angular momentum
= Moment of inertia $\times$ angular velocity
$=[ML^2][T^{-1}]$
$=[ML^2T^{-1}]$
Work = Force $\times$ distance
$=[MLT^{-2}][L]$
$=[ML^2T^{-2}]$
Energy $=[ML^2T^{-2}]$
Torque = Force $\times$ distance
$=[MLT^{-2}][L]$
$=[ML^2T^{-2}]$
Young's modulus
$=\frac{\text{Force / Area}}{\text{Change in length / original length}}$
$=\frac{[MLT^{-2}]/[L^2]}{[L]/[L]}$
$=[ML^{-1}T^{-2}]$
Hence, among the given pair of physical quantities work and torque have the same dimensions
$[ML^2T^{-2}]$.