The oxidation number of Pt in [Pt(en)2Cl2]2+ is :
Show Hint
- + 3
- + 4
- + 2
- + 6
The Correct Option is B
Solution and Explanation
Step 1: Ethylenediamine (en) is a neutral bidentate ligand, charge 0; each chloride is \(-1\), so two give \(-2\).
Step 2: Let Pt be \(x\). The complex ion carries \(+2\):
\[x + 2(0) + 2(-1) = +2 \Rightarrow x - 2 = +2 \Rightarrow x = +4\]Answer: \(\boxed{+4}\), option (B).
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