The number of points on the curve \(y=54 x^5-135 x^4-70 x^3+180 x^2+210 x\) at which the normal lines are parallel \(to x+90 y+2=0\) is
Normal of line is parallel to line x+90y+2=0
\(m_N=−\frac{1}{90}\)
\(−(\frac{dx}{dy})_{(x_1y_1)}=−\frac{1}{90}⇒(\frac{dy}{dx})_{(x_1y_1)}=90\)
Now,
\(\frac{dy}{dx}=270x^4−540x^3−210x^2+360x+210=90\)
\(⇒x=1,2,\frac{−2}{3},\frac{−1}{3}\)
so, the correct option is(B): 4 normals
If f(x) = ex, h(x) = (fof) (x), then \(\frac{h'(x)}{h'(x)}\) =
If some other quantity ‘y’ causes some change in a quantity of surely ‘x’, in view of the fact that an equation of the form y = f(x) gets consistently pleased, i.e, ‘y’ is a function of ‘x’ then the rate of change of ‘y’ related to ‘x’ is to be given by
\(\frac{\triangle y}{\triangle x}=\frac{y_2-y_1}{x_2-x_1}\)
This is also known to be as the Average Rate of Change.
Consider y = f(x) be a differentiable function (whose derivative exists at all points in the domain) in an interval x = (a,b).
Read More: Application of Derivatives