The number of oxygen atoms present in chemical formula of fuming sulphuric acid is _______.
The chemical formula for fuming sulfuric acid is $\text{HSO}_3\text{SO}_3$, also known as oleum.
The number of oxygen atoms in the formula is calculated by counting the oxygens in both parts of the formula:
- $\text{HSO}_3$ contributes 3 oxygen atoms. - $\text{SO}_3$ contributes 3 oxygen atoms.
Thus, the total number of oxygen atoms in fuming sulfuric acid is $3 + 3 + 1 = 7$. Therefore, the correct answer is 7.
List-I (Oxoacids of Sulphur) | List-II (Bonds) | ||
A | Peroxodisulphuric acid | I | Two S–OH, Four S=O, One S–O–S |
B | Sulphuric acid | II | Two S–OH, One S=O |
C | Pyrosulphuric acid | III | Two S–OH, Four S=O, One S–O–O–S |
D | Sulphurous acid | IV | Two S–OH, Two S=O |
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is: