The number of optical isomers exhibited by the iron complex (A) obtained from the following reaction is ______
$ FeCl_3 + KOH + H_2C_2O_4 \rightarrow A $
Show Hint
Correct Answer: 2
Approach Solution - 1
The reaction provided involves FeCl3, KOH, and H2C2O4. The product formed, A, is likely a complex iron compound. Let's follow the steps to determine the number of optical isomers.
Step 1: Determine the Iron Complex
The reaction of FeCl3 with oxalic acid (H2C2O4) in the presence of KOH generally forms a complex known as potassium ferrioxalate, K3[Fe(C2O4)3].
Step 2: Identify the Coordination Sphere
The coordination number for iron (Fe) in K3[Fe(C2O4)3] is 6, as oxalate (C2O4) is a bidentate ligand, each donating two pairs of electrons.
Step 3: Understand Optical Isomerism
Optical isomerism occurs in complexes where the arrangement of ligands can exist as non-superimposable mirror images. For the complex K3[Fe(C2O4)3], this occurs because the oxalate ligands create a chiral center around the metal.
Step 4: Identify and Count the Optical Isomers
K3[Fe(C2O4)3] has two non-superimposable mirror images or enantiomers, known as the 'Δ' and 'Λ' forms, making a total of 2 optical isomers.
Conclusion
The number of optical isomers is 2. This solution falls perfectly within the given range of 2 to 2.
Approach Solution -2
\( FeCl_3 + KOH + H_2C_2O_4 \rightarrow K_3[Fe(C_2O_4)_3] \)
\([Fe(C_2O_4)_3]^{3-} \text{ is } [M(AA)_3] \text{ type complex.} \)
So total optical isomers = 2
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