Question:
The most active metabolite of Vitamin-D, which helps in the regulation of calcium and phosphorus metabolism is:
The most active metabolite of Vitamin-D, which helps in the regulation of calcium and phosphorus metabolism is:
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1,25-(OH)2D3 (Calcitriol):
- Active form of vitamin D.
- Regulates calcium homeostasis.
- 25-OH-D3 is the major circulating form.
- Active form of vitamin D.
- Regulates calcium homeostasis.
- 25-OH-D3 is the major circulating form.
Updated On: Sep 1, 2026
- 1-hydroxy Cholecalciferol
- 25-hydroxy Cholecalciferol
- 1,25-dihydroxy Cholecalciferol
- Ergocalciferol
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The Correct Option is C
Solution and Explanation
Step 1: Understanding the Question:
This question tests knowledge of Vitamin D metabolism.
Step 2: Detailed Explanation:
1,25-dihydroxy Cholecalciferol (calcitriol) is the most active metabolite of Vitamin D.
It regulates calcium and phosphorus metabolism.
25-hydroxy Cholecalciferol (B): The major circulating form (not the most active).
1-hydroxy Cholecalciferol (A): Not the most active.
Ergocalciferol (D): Vitamin D2 (plant source, less active).
Thus, 1,25-dihydroxy Cholecalciferol is the correct answer.
Step 3: Final Answer:
Thus, 1,25-dihydroxy Cholecalciferol is the most active metabolite, which corresponds to option (C).
[0.5cm]
This question tests knowledge of Vitamin D metabolism.
Step 2: Detailed Explanation:
1,25-dihydroxy Cholecalciferol (calcitriol) is the most active metabolite of Vitamin D.
It regulates calcium and phosphorus metabolism.
25-hydroxy Cholecalciferol (B): The major circulating form (not the most active).
1-hydroxy Cholecalciferol (A): Not the most active.
Ergocalciferol (D): Vitamin D2 (plant source, less active).
Thus, 1,25-dihydroxy Cholecalciferol is the correct answer.
Step 3: Final Answer:
Thus, 1,25-dihydroxy Cholecalciferol is the most active metabolite, which corresponds to option (C).
[0.5cm]
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