The mass of helium atom of mass number $4$ is $4.0026$ amu, while that of the neutron and proton are $1.0087$ and $1.0078$ respectively on the same scale. Hence, the nuclear binding energy per nucleon in the helium atom is nearly
- 5 MeV
- 7 MeV
- 10 MeV
- 14 MeV
The Correct Option is B
Solution and Explanation
Hence,
$ \Delta m=(2\times 1.0078+2\times 1.0087)-4.0026 $
$ =0.0304\,amu $
$ \therefore $ energy released
$ =0.0304\times 931.5\,MeV $
$ =28.3\,MeV $
Binding energy per nucleon
$ =\frac{28.3}{4}=7\,MeV $ (approximately)
Top Questions on Nuclear physics
- ${ }_{92}^{238} U$ is known to undergo radioactive decay to form ${ }_{82}^{206} Pb$ by emitting alpha and beta particles. A rock initially contained $68 \times 10^{-6} g$ of ${ }_{92}{ }^{238} U$. If the number of alpha particles that itwould emit during its radioactive decay of ${ }_{92}^{238} U$ to ${ }_{82}{ }^{206} Pb$ in three half-lives is $Z \times 10^{18}$, then what is the value of $Z$ ?
- JEE Advanced - 2020
- Chemistry
- Nuclear physics
- $C_{6}H_{5}F^{18}$ is a $F^{18}$ radio-isotope labelled organic compound. $F^{18}$ decays by positron emission. the product resulting on decay is
- WBJEE - 2017
- Chemistry
- Nuclear physics
- $1 \,g$ of $U -235$ is converted into $UF _{6}$. The radioactivity of $UF _{6}$ thus obtained is :
- BITSAT - 2011
- Chemistry
- Nuclear physics
- Bombardment of aluminium by a-particle leads to its artificial disintegration in two ways, (i) and (ii) as shown. Products X , Y and Z respectively, are
- JEE Advanced - 2011
- Chemistry
- Nuclear physics
- If the bond dissociation energies of $X Y, X_{2}$ and $Y_{2}$ (all diatomic molecules) are in the ratio of $1: 1: 0.5$ and $\Delta H_{f}$ for the formation of $X Y$ is $-200\, kJ \,mol ^{-1}$. The bond dissociation energy of $X_{2}$ will be
- AIIMS - 2011
- Chemistry
- Nuclear physics
Questions Asked in MU OET exam
- Alzheimers disease affects
- MU OET - 2013
- Common Diseases in Human Beings
- Which antibiotic act on the cell wall of bacteria?
- MU OET - 2013
- Common Diseases in Human Beings
- Periodic appearence of malaria symptoms occurs due to periodic
- MU OET - 2013
- Common Diseases in Human Beings
- Agar-Agar is obtained from
- Lymph (nodes) glands form
- MU OET - 2013
- body fluids and circulation
Concepts Used:
Nuclear Physics
Nuclear physics is the field of physics that studies atomic nuclei and their constituents and interactions, in addition to the study of other forms of nuclear matter. Nuclear physics should not be confused with atomic physics, which studies the atom as a whole, including its electrons
Radius of Nucleus
‘R’ represents the radius of the nucleus. R = RoA1/3
Where,
- Ro is the proportionality constant
- A is the mass number of the element
Total Number of Protons and Neutrons in a Nucleus
The mass number (A), also known as the nucleon number, is the total number of neutrons and protons in a nucleus.
A = Z + N
Where, N is the neutron number, A is the mass number, Z is the proton number
Mass Defect
Mass defect is the difference between the sum of masses of the nucleons (neutrons + protons) constituting a nucleus and the rest mass of the nucleus and is given as:
Δm = Zmp + (A - Z) mn - M
Where Z = atomic number, A = mass number, mp = mass of 1 proton, mn = mass of 1 neutron and M = mass of nucleus.
SUBSCRIBE TO OUR NEWS LETTER
