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The locus of the centre of a circle which touches externally the circle x2 + y2 - 6x - 6y + 14 = 0 and also touches the y-axis is given by the equation
The locus of the centre of a circle which touches externally the circle x2 + y2 - 6x - 6y + 14 = 0 and also touches the y-axis is given by the equation
Updated On: Oct 7, 2024
- x 2 - 6x - 10y + 14 = 0
- x 2 - 10x - 6y + 14 = 0
- y 2 - 6x - 10y + 14 = 0
- y 2 - 10x - 6y + 14 = 0
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The Correct Option is D
Solution and Explanation
The correct option is (D): y 2 - 10x - 6y + 14 = 0
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