Question:

The incorrect statement is :

Updated On: Sep 30, 2024
  • $Cu^{2+}$ salts give red coloured borax bead test in reducing flame
  • $Cu^{2+}$ and $Ni^{2+}$ ions give black precipitate with $H_2S$ in presence of $HCl$ solution
  • Ferric ion gives blood red colour with potassium thiocyanate
  • $Cu^{2+}$ ion gives chocolate coloured precipitate with potassium ferrocyanide solution
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The Correct Option is B

Solution and Explanation

$Cu ^{2+}$ and $Ni ^{2+}$ ions belong to Group II and Group IV, respectively,

$Cu ^{2+}+ H _{2} S \stackrel{ dil . HCl }{\longrightarrow} \underset{( B k \times k )}{ CuS } \downarrow$
$Ni ^{2+}+ H _{2} S \stackrel{ NH _{4} OH }{\longrightarrow} \underset{( Bhd )}{ NiS } \downarrow$

Group II sulphides precipitated out even under low concentration of sulphides, while Group IV sulphides require higher concentration of sulphides.

To fulfill this reaction condition, dil. HCl is chosen in Group II reagents and $NH _{4} OH$ is chosen in Group IV reagents.
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Concepts Used:

D and F Block Elements

The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements. 

They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.

Read More: The d and f block elements