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The first ionisation potential of $Na$ is $5.1\, eV$. The value of electron gain enthalpy of $Na^+$ will be
The first ionisation potential of $Na$ is $5.1\, eV$. The value of electron gain enthalpy of $Na^+$ will be
Updated On: Jun 23, 2024
- $- 2.55\, eV$
- $- 5.1\, eV$
- $- 10.2\, eV$
- $+ 2.55\, eV$
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The Correct Option is B
Solution and Explanation
$\, \, \, \, \, \, Na \longrightarrow Na^+ + e^- \, First \, IE$
$Na^+ + e^- \longrightarrow Na$
Electron gain enthalpy of Na+ is reverse of (IE) Because reaction is reverse so
$ \, \, \, \, \, ? H (eq) = - 5.1 \, eV$
$Na^+ + e^- \longrightarrow Na$
Electron gain enthalpy of Na+ is reverse of (IE) Because reaction is reverse so
$ \, \, \, \, \, ? H (eq) = - 5.1 \, eV$
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Haloalkanes and Haloarenes - Classification
Classification of Haloalkanes and Haloarenes are as follows:
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These are further classified as mono, di, or polyhalogen (tri-,tetra-, etc.) compounds depending on whether they contain one, two or more halogen atoms in their structures. For example;
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