The equations of the tangents drawn from the origin to the circle $x^2 + y^2 + 2 rx + 2hy + h^2 = 0, $ are
- x = 0
- y-0
- $(h^2 - r^2)x-2rhy=0 $
- $(h^2 - r^2)x+2rhy=0 $
The Correct Option is C
Solution and Explanation
of tangent be y = m x
$\Rightarrow $ Length of perpendicular from origin = radius
$\Rightarrow \hspace25mm \frac{| mr+h |}{\sqrt{m^2+1}}=r$
$\Rightarrow \hspace15mm m^2r^2+h^2+2mrh=r^2(m^2+1)$
$\Rightarrow \hspace30mm m=\Bigg|\frac{r^2-h^2}{2rh}\Bigg|, m=\infty$
$\therefore Equation of tangents are y=\Bigg|\frac{r^2-h^2}{2rh}\Bigg|x,x=0$
Therefore (a) and (c) are the correct answers
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