Question

The electronegativity of the Silicon (Si) atom using Allred-Rochow scale of electronegativity is. Given: The covalent radius for Si atom = 1.175 Angstrom.

• A. 2.40
• B. 2.50
• C. 2.20
• D. 2.10

Hint:

The Allred-Rochow electronegativity scale uses the covalent radius to determine the electronegativity of an atom.

Answer 1

The Correct Option is C

Step 1: Allred-Rochow Electronegativity Formula.
The Allred-Rochow electronegativity (\( \chi \)) is given by the formula: \[ \chi = \frac{0.359}{r} + 0.744 \] where \( r \) is the covalent radius in Angstroms.

Step 2: Apply the Formula for Si.
For Silicon (Si), the covalent radius \( r = 1.175 \, \text{Å} \). Substituting the value into the formula: \[ \chi = \frac{0.359}{1.175} + 0.744 = 0.305 + 0.744 = 2.20 \]

Step 3: Conclusion.
Therefore, the electronegativity of Silicon (Si) is 2.20, corresponding to option (3).