Question

The distance travelled by a particle starting from rest and moving with an acceleration $\frac{4}{3}ms^{-2},$ in the third second is

• A. $\frac{10}{3}m$
• B. $\frac{19}{3}m$
• C. $6\, m$
• D. $4\, m$

Answer 1

The Correct Option is A

Distance travelled in the $3^{rd}$ second
= Distance travelled in $3\,s$
- distance travelled in 2 s.
As, u = 0,
$S_{(3^{rd}s)}=\frac{1}{2}a.3^2 -\frac{1}{2}a.2^2=\frac{1}{2}.a.5$
Given $a=\frac{4}{3}ms^{-2}; \therefore \, \, \, \, S_{(3^{rd}s)} =\frac{1}{2} \times \frac{4}{3} \times 5 =\frac{10}{3}m$