To find the Van't Hoff factor (\(i\)) for the formic acid solution, we use the depression in freezing point formula:
\(\Delta T_f = i \cdot K_f \cdot m\)
Where:
The given concentration of formic acid is \(5 \, mL \, L^{-1}\). First, we calculate the molality.
Step 1: Calculate the mass of formic acid in 1 L of solution.
Density of formic acid = \(1.05 \, g \, mL^{-1}\).
Mass of formic acid in \(5 \, mL\) is:
\(\text{Mass} = \text{Volume} \times \text{Density} = 5 \times 1.05 = 5.25 \, g\)
Step 2: Calculate the number of moles of formic acid.
Molar mass of formic acid (HCOOH) = \(2 \times 1 + 12 + 16 \times 2 = 46 \, g \, mol^{-1}\).
Number of moles = \(\frac{5.25}{46} \approx 0.1141 \, mol\).
Step 3: Calculate the molality.
Since the solution is prepared in 1 liter of water, the mass of water is approximately \(1000 \, g = 1 \, kg\).
Molality \((m) = 0.1141 \, mol \, kg^{-1}\).
Step 4: Calculate the Van't Hoff factor.
Rearranging the formula for Van't Hoff factor:
\(i = \frac{\Delta T_f}{K_f \cdot m} = \frac{0.0405}{1.86 \times 0.1141} \approx 1.9\)
Therefore, the Van't Hoff factor of the formic acid solution is approximately 1.9, which corresponds to the correct option.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| Sample | Van't Haff Factor |
|---|---|
| Sample - 1 (0.1 M) | \(i_1\) |
| Sample - 2 (0.01 M) | \(i_2\) |
| Sample - 3 (0.001 M) | \(i_2\) |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: