The densities of graphite and diamond at $298\, K$ are $2.25$ and $3.31\, g\, cm^{-3},$ respectively. If the standard free energy difference $(\Delta G^{\circ})$ is equal to $1895\, J\, mol^{-1}$, the pressure at which graphite will be transformed into diamond at $298\, K$ is -
- $9.92 \times 10^8 \, Pa $
- $9.92 \times 10^7 \, Pa $
- $9.92 \times 10^6 \, Pa $
- $9.92 \times 10^5 \, Pa $
The Correct Option is A
Solution and Explanation
$9.92 \times 10^8 \; Pa$
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Concepts Used:
Gibbs Free Energy
The energy associated with a chemical reaction that can be used to do work.It is the sum of its enthalpy plus the product of the temperature and the entropy (S) of the system.
The Gibbs free energy is the maximum amount of non-expansion work that can be extracted from a thermodynamically closed system. In completely reversible process maximum enthalpy can be obtained.
ΔG=ΔH−TΔS
The Conditions of Equilibrium
If both it’s intensive properties and extensive properties are constant then thermodynamic system is in equilibrium. Extensive properties imply the U, G, A.
