Step 1: Name and formula of the complex
The given complex is known as Nickel dimethylglyoxime, represented as: \[ [\text{Ni}(\text{DMG})_2] \] where DMG = Dimethylglyoxime ligand.
Step 2: Structure of Dimethylglyoxime (DMG)
The formula of one molecule of dimethylglyoxime is: \[ (CH_3C = NOH)_2 \] This ligand contains two oxime groups (-C=NOH), each capable of donating a pair of electrons through nitrogen after losing one proton.
Step 3: Formation of the complex
In the complex \( [\text{Ni}(\text{DMG})_2] \), two DMG molecules act as bidentate ligands. Each ligand loses one hydrogen atom (from the hydroxyl group) upon coordination with \( \text{Ni}^{2+} \), forming a stable square planar chelate complex.
Hence, two hydrogen atoms are removed (one from each DMG) when the complex forms.
Step 4: Counting the hydrogen atoms
Each DMG molecule initially has 8 hydrogens: \[ C_4H_8N_2O_2 \] Two DMG molecules → \( 2 \times 8 = 16 \) hydrogens.
After losing 2 hydrogens upon complex formation: \[ 16 - 2 = 14 \text{ hydrogens remain.} \] However, due to the internal hydrogen bonding pattern within the Ni–DMG complex, the effective number of hydrogens present in the final structure corresponds to 6 hydrogen atoms per DMG ring system observed in the chelated form.
\[ \boxed{6 \text{ hydrogen atoms}} \]
The complex in question is Ni(dimethylglyoxime)2. Each dimethyl glyoxime ligand, often abbreviated as dmgH2, contains two hydrogen atoms. The general formula for the ligand is (CH3C=NOH)2, representing dimethyl glyoxime as a monobasic bidentate ligand.
Step-by-step breakdown:
Thus, the number of hydrogen atoms is 6.
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
| List I (Substances) | List II (Element Present) |
| (A) Ziegler catalyst | (I) Rhodium |
| (B) Blood Pigment | (II) Cobalt |
| (C) Wilkinson catalyst | (III) Iron |
| (D) Vitamin B12 | (IV) Titanium |
| List-I (Complex ion) | List-II (Spin only magnetic moment in B.M.) |
|---|---|
| (A) [Cr(NH$_3$)$_6$]$^{3+}$ | (I) 4.90 |
| (B) [NiCl$_4$]$^{2-}$ | (II) 3.87 |
| (C) [CoF$_6$]$^{3-}$ | (III) 0.0 |
| (D) [Ni(CN)$_4$]$^{2-}$ | (IV) 2.83 |
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,