Question:

The area of the region \(\{ {(x, y): 0 ≤ x ≤ \frac{9}{4}, 0 ≤ y ≤ 1, x ≥ 3y, x + y ≥ 2}\}\)

Updated On: Aug 4, 2024
  • \(\frac{11}{32}\)

  • \(\frac{35}{96}\)

  • \(\frac{37}{96}\)

  • \(\frac{13}{32}\)

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The Correct Option is A

Solution and Explanation

area of triangle
Area of required region
\(=\frac{1}{2} (\frac{2}{3}+\frac{3}{4})\frac{1}{4}+\frac{1}{2} \times\frac{2}{3} \times\frac{1}{2}\)
\(=\frac{11}{32}\)

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