Question:

The angle between vector \( \vec{Q} \) and the resultant of \( (2\vec{Q} + 2\vec{P}) \) and \( (2\vec{Q} - 2\vec{P}) \) is:

Updated On: Nov 21, 2024
  • \( 0^\circ \)
  • \( \tan^{-1}\left(\frac{2\vec{Q} - 2\vec{P}}{2\vec{Q} + 2\vec{P}}\right) \)
  • \( \tan^{-1}\left(\frac{P}{Q}\right) \)
  • \( \tan^{-1}\left(\frac{2Q}{P}\right) \)
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The Correct Option is A

Solution and Explanation

The resultant vector is given by:

\[ \vec{R} = (2\vec{Q} + 2\vec{P}) + (2\vec{Q} - 2\vec{P}) = 4\vec{Q} \]

The angle between \(\vec{Q}\) and \(\vec{R}\) is \(0^\circ\) as they are in the same direction. Therefore, Option (1) is correct.

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