To solve this question, we must match each spectral series for the hydrogen atom from List I with the corresponding spectral region or higher energy state in List II. Here is the detailed explanation:
After matching each series with the respective spectral region, the correct option is:
| List I (Spectral Series) | List II (Spectral Region) |
|---|---|
| A. Lyman | II. UV region |
| B. Balmer | IV. Visible region |
| C. Paschen | III. Infrared region |
| D. Pfund | I. Infrared region |
Therefore, the correct answer is: A-II, B-IV, C-III, D-I.
The correct matching is as follows:
- A. Lyman series corresponds to the UV region (II) as it involves transitions to the \( n=1 \) energy level.
- B. Balmer series corresponds to the Visible region (IV) as it involves transitions to the \( n=2 \) energy level.
- C. Paschen series corresponds to the Infrared region (III) as it involves transitions to the \( n=3 \) energy level.
- D. Pfund series corresponds to the Infrared region (I) as it involves transitions to the \( n=5 \) energy level.
The Correct Answer is: \( A - II, B - IV, C - III, D - I \)
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)

Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,