Question

$\text{A constant current was passed through a solution of AuCl}_4^- \text{ ion between gold electrodes. After a} \\\text{period of 10.0 minutes, the increase in mass of cathode was 1.314 g. The total charge passed} \\$$\text{through the solution is \_\_\_\_\_\_\_\_} \times 10^{-2} \, \text{F.} \\$$\text{(Given atomic mass of Au = 197)}$

Answer 1

Correct Answer: 2

Solution:  

\(\frac{W}{E} = \frac{\text{charge}}{1F}\)

Substitute the values:  
\(\frac{1.314}{\frac{197}{3}} = \frac{Q}{1F}\)

\(Q = 2 \times 10^{-2} F\)

The Correct Answer is: 2