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Ten identical cells each emf 2V and internal resistance 1Ω are connected in series with two cells wrongly connected. A resistor of 10Ω is connected to the combination. What is the current through the resistor?
Ten identical cells each emf 2V and internal resistance 1Ω are connected in series with two cells wrongly connected. A resistor of 10Ω is connected to the combination. What is the current through the resistor?
Updated On: Sep 7, 2024
- 2.4 A
- 0.6 A
- 1.2 A
- 1.8 A
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The Correct Option is B
Solution and Explanation
The correct answer is (B) : 0.6 A.
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