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Some iron beads are embedded in wax ball which is just floating in water. The volume of ball is $18 \,cm^{3}$ and relative density of wax is $0.9$. Then mass of the iron trapped in the ball is
Some iron beads are embedded in wax ball which is just floating in water. The volume of ball is $18 \,cm^{3}$ and relative density of wax is $0.9$. Then mass of the iron trapped in the ball is
Updated On: Aug 15, 2022
- $1.8\, g$
- $2.7\,g$
- $16.8\, g$
- $8.1 \,g$
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The Correct Option is A
Solution and Explanation
Let mass of iron = m
According to law of floatation
Weight = upthrust
(m + mass of wax)$g = 18 \times 1 \times g$
Ignoring the volume of iron since it is in the form of small beads
$\therefore m+18 \times 0.9=18\times 1$
$m=1.8\,g$
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Concepts Used:
Gravitation
In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.
Newton’s Law of Gravitation
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
- F ∝ (M1M2) . . . . (1)
- (F ∝ 1/r2) . . . . (2)
On combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2
The dimension formula of G is [M-1L3T-2].
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