Question:

Read the following two statements
Statement I: Ionic radius of Li+ is greater than Mg++
Statement II: Lithium and magnesium can't form superoxide

Updated On: Jul 15, 2024
  • Both Statement I and Statement II are correct.
  • Both Statement I and Statement II are incorrect.
  • Statement I is correct but Statement II is incorrect.
  • Statement I is incorrect but Statement II is correct.
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

The correct option is (A): (1) Both Statement I and Statement II are correct.
Radius of \(Li^+=76 pm\) whereas \(Mg^+\) is \(72 pm\). Both Li and Mg are unable to form peroxide because of their small size.
Was this answer helpful?
0
0

Concepts Used:

Group 1 Elements

Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkali metals are characterized by one s-electron in the valence shell of their atoms.

Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:

  • Lithium(Li)
  • Sodium(Na)
  • Potassium (K)
  • Rubidium (Ru)
  • Cesium (Cs)
  • Francium (Fr)

They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.

Electronic Configuration:

  • Alkali metals have one electron in their valence shell.
  • The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
  • They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).

This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.