Question:

Potential at the equivalence point for a redox reaction
\(\mathrm{aOX1} + \mathrm{bRED2} \rightleftharpoons \mathrm{bOX2} + \mathrm{aRED1}\)
is given by the equation:

Updated On: Jul 12, 2024
  • \(E=\frac{(bE_1^0+aE_2^0)}{(a+b)}\)
  • \(E=E^0+(\frac{0.0592}{n})X logQ\)
  • \(E=E^0+(\frac{0.0592}{n})X log(\frac{Red}{OX})\)
  • \(E=E_1^0+\frac{E_2^0}{2}\)
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The Correct Option is A

Solution and Explanation

The correct option is (A):\(E=\frac{(bE_1^0+aE_2^0)}{(a+b)}\)
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