Question

Plotting \(\frac{1}{Λ_{m}}\) against \(cΛ_{m}\) for aqueous solutions of a monobasic weak acid (HX) resulted in a straight line with y-axis intercept of P and slope of S. The ratio \(\frac{P}{S}\) is 
[\(Λ_{m}\) = molar conductivity, 
\(Λ^{o}_{m}\)= limiting molar conductivity, 
\(c\) = molar concentration, 
\(K_{a}\) = dissociation constant of HX]

• A. \(K_a Λ^o_m\)
• B. \(K_a \frac{Λ^o_m}{2}\)
• C. \(2 K_a Λ^o_m\)
• D. \(\frac{1}{(K_a Λ^o_m)}\)

Answer 1

The Correct Option is A

Correct option is (A) Ka Λ°_m.

When plotting 1/Λm​ against cΛm​ for aqueous solutions of a monobasic weak acid (HX), a linear relationship is observed, yielding a straight line with a y-axis intercept of P and a slope of S. The ratio P/S can be represented as:

0P/S=Ka​1​+Λm0​

Where:

• Λm​ is the molar conductivity,
• Λm0​ is the limiting molar conductivity,
• c is the molar concentration,
• Ka​ is the dissociation constant of HX.