Question

One mole of an ideal monatomic gas undergoes a cyclic process as shown in the figure. The total heat supplied to the gas is:

• A. 800 J
• B. 400 J
• C. 500 J
• D. 600 J

Hint:

For any cyclic process, \[ \Delta U = 0 \] Therefore net heat supplied equals net work done.

Answer 1

The Correct Option is D

Concept:

• For a cyclic process, \[ \Delta U = 0 \]

• Hence, \[ Q_{\text{net}} = W_{\text{net}} \]

• Work done in a cycle equals the area enclosed in the \(P-V\) diagram.

Step 1: Read the dimensions of the rectangle.
From the graph, \[ \Delta P = 300-100=200\;{\rm N\,m^{-2}} \] and \[ \Delta V = 5-2=3\;{\rm m^3} \]

Step 2: Calculate the area enclosed.
\[ W = \Delta P \times \Delta V \] \[ W = 200\times 3 \] \[ W = 600\;{\rm J} \]

Step 3: Use cyclic process condition.
\[ Q=W \] \[ Q=600\;{\rm J} \] \[ \boxed{\text{Option (D)}} \]