Number of \( ^1H \) NMR signals observed for the following compound is .............
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In \( ^1H \) NMR, protons in equivalent environments (like the two methyl groups here) give a single signal, while protons in different environments (like the alkene proton) give separate signals.
The structure of the compound consists of two methyl groups (Me) attached to a double bond. The protons in the compound will have different environments based on their symmetry.
Step 1: Identify the types of protons.
- The two methyl groups (Me) are identical and will give a single signal in the \( ^1H \) NMR spectrum.
- The proton on the alkene (C-H) will be in a distinct environment and will give a separate signal. Step 2: Count the number of distinct signals.
- There is one signal for the two methyl protons, as both methyl groups are equivalent.
- There is one signal for the proton attached to the double bond.
Thus, the total number of distinct \( ^1H \) NMR signals observed is 2. Final Answer:
\[
\boxed{2}
\]
