Match List I with List II
List-I Reaction List-II Reagents (A) Hoffmann Degradation (I) Conc.KOH,\(\triangle\) (B) Clemenson reduction (II) CHCl3, NaOH/H3O+ (C) Cannizaro reaction (III) Br2, NaOH (D) Reimer-Tiemann Reaction (IV) Zn-Hg/HCl
Choose the correct answer from the option given below:
Match List I with List II
| List-I | Reaction | List-II | Reagents |
| (A) | Hoffmann Degradation | (I) | Conc.KOH,\(\triangle\) |
| (B) | Clemenson reduction | (II) | CHCl3, NaOH/H3O+ |
| (C) | Cannizaro reaction | (III) | Br2, NaOH |
| (D) | Reimer-Tiemann Reaction | (IV) | Zn-Hg/HCl |
Choose the correct answer from the option given below:
Show Hint
For reaction and reagent matching:
• Focus on identifying the reagents specific to each reaction’s mechanism.
• Recall key reagents used for reductions, substitutions, or rearrangements in named reactions.
- (A)-III, (B) -IV, (C) – II, (D)-I
- (A)-III, (B) -IV, (C) –I, (D)-II
- (A)-II, (B) -IV, (C) –I, (D)-III
- (A)-II, (B) -I, (C) – III, (D)-IV
The Correct Option is B
Solution and Explanation
- Hoffmann Degradation Reaction: This reaction uses Br2 and NaOH to convert amides into amines. Reagent: (III).
- Clemenson Reduction: This reaction reduces ketones or aldehydes to alkanes using Zn-Hg in HCl. Reagent: (IV).
- Cannizzaro Reaction: This reaction involves disproportionation of aldehydes without α-hydrogen in concentrated alkali. Reagent: (I).
- Reimer-Tiemann Reaction: This reaction introduces a −CHO group to phenols using CHCl3 and NaOH. Reagent: (II).
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