| List - IMolecule | List - IIBond enthalpy (kJ mol-1) |
|---|---|
| (A) HCl | (I) 435.8 |
| (B) N2 | (II) 498 |
| (C) H2 | (III) 946.0 |
| (D) O2 | (IV) 431.0 |
Bond enthalpy is the energy required to break one mole of a particular bond in a gaseous substance.
A. HCl: The H-Cl bond enthalpy is approximately 431 kJ mol$^{-1}$ (slightly lower than HBr and higher than HF due to periodic trends down the halogen group). Thus, A-IV.
B. N$_2$: The N≡N triple bond is very strong, with a bond enthalpy of approximately 946 kJ mol$^{-1}$. Thus, B-III.
C. H$_2$: The H-H single bond has a bond enthalpy of approximately 436 kJ mol$^{-1}$. Thus, C-I.
D. O$_2$: The O=O double bond has a bond enthalpy of approximately 498 kJ mol$^{-1}$. Thus, D-II.
Therefore, the correct matching is A-IV, B-III, C-I, D-II.
Resonance in X$_2$Y can be represented as 
The enthalpy of formation of X$_2$Y is 80 kJ mol$^{-1}$, and the magnitude of resonance energy of X$_2$Y is:
Given below are two statements :
Statement I : Wet cotton clothes made of cellulose based carbohydrate takes comparatively longer time to get dried than wet nylon polymer based clothes.
Statement II : Intermolecular hydrogen bonding with water molecule is more in nylon-based clothes than in the case of cotton clothes.
In the light of the above statements, choose the Correct answer from the options given below
Match the LIST-I with LIST-II
| LIST-I | LIST-II |
| A. PF5 | I. dsp2 |
| B. SF6 | II. sp3d |
| C. Ni(CO)4 | III. sp3d2 |
| D. [PtCl4]2- | IV. sp3 |
Choose the correct answer from the options given below:
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.