
To solve the problem of matching reactions with their respective reagents, we need to identify which reagents correspond to each reaction in the provided lists.
Thus, the correct matching of List-I with List-II is (A)-(IV), (B)-(III), (C)-(I), (D)-(II).
(A) Oxidation of phenol to benzoquinone: This reaction uses \( \text{Na}_2\text{Cr}_2\text{O}_7 \) and \( \text{H}_2\text{SO}_4 \) as the oxidizing agents.
(B) Kolbe’s reaction: It involves carboxylation of phenol using \( \text{NaOH} \) and \( \text{CO}_2 \), followed by acidification with \( \text{HCl} \).
(C) Reimer-Tiemann reaction: This reaction introduces an aldehyde group on the phenol ring using \( \text{NaOH} \) and \( \text{CHCl}_3 \).
(D) Williamson’s synthesis: It prepares ethers by reacting phenoxide with \( \text{CH}_3\text{Cl} \) in the presence of \( \text{NaOH} \).
The Correct answer is: (A)-(IV), (B)-(III), (C)-(I), (D)-(II)
Structures of four disaccharides are given below. Among the given disaccharides, the non-reducing sugar is: 
The temperature at which the rate constants of the given below two gaseous reactions become equal is ____________ K (Nearest integer).
\[ X \longrightarrow Y, \qquad k_1 = 10^{6} e^{-\frac{30000}{T}} \] \[ P \longrightarrow Q, \qquad k_2 = 10^{4} e^{-\frac{24000}{T}} \] Given: \( \ln 10 = 2.303 \)
Structures of four disaccharides are given below. Among the given disaccharides, the non-reducing sugar is: 