Question:

Magnesium wire continues to burn in the atmosphere of $CO_2$,though $CO_2$ is not a supporter of combustion because

Updated On: Jul 6, 2022
  • Mg acts as an oxidising agent
  • Mg has high ionization energy
  • Mg acts as a reducing agent and removes oxygen from $CO_2$
  • All of the above
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The Correct Option is C

Solution and Explanation

Mg is more electropositive than carbon and has more affinity for $O_2$ than that of C. As such the enthalpy of formation of MgO is more than that of $CO_2$, therefore, Mg continues to bum in $CO_2$ $ {CO_2 + 2Mg -> 2MgO + C}$
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Concepts Used:

Group 1 Elements

Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkali metals are characterized by one s-electron in the valence shell of their atoms.

Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:

  • Lithium(Li)
  • Sodium(Na)
  • Potassium (K)
  • Rubidium (Ru)
  • Cesium (Cs)
  • Francium (Fr)

They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.

Electronic Configuration:

  • Alkali metals have one electron in their valence shell.
  • The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
  • They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).

This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.