Question:

Klenow fragment is the modified enzyme of which DNA polymerase:

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Klenow = DNA Pol I minus its “Front-end” ($5'\to3'$) exonuclease.
Updated On: May 28, 2026
  • DNA polymerase I
  • DNA polymerase II
  • DNA polymerase III
  • DNA polymerase IV
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The Correct Option is A

Solution and Explanation

Step 1: Concept
DNA Polymerase I in E. coli has three activities: $5'\to3'$ polymerase, $3'\to5'$ exonuclease, and $5'\to3'$ exonuclease.

Step 2: Meaning

The Klenow fragment is produced when DNA Polymerase I is treated with the protease subtilisin.

Step 3: Analysis

This cleavage removes the $5'\to3'$ exonuclease domain, leaving a large fragment retaining polymerase and proofreading functions.

Step 4: Conclusion

The Klenow fragment is specifically a derivative of DNA Polymerase I.

Final Answer: (1)
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