$K, Rb$ and $Cs$ form superoxides. The stability of the superoxides increases from '$K$' to '$Cs$' due to decrease in lattice energy. The correct answer is

$K , Rb, Cs$ from superoxides when they are burned in the air .as we move down the group, the size of an atom from $k$ to $Cs$ increases so, lattice energy decreases and hence the stability of superoxide also decreases.

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are true but (R) is not the correct explanation of (A)

(A) is true but (R) is not true

(A) is not true but (R) is true

$K, Rb$ and $Cs$ form superoxides. The stability of the superoxides increases from '$K$' to '$Cs$' due to decrease in lattice energy. The correct answer is

Both (A) and (R) are true and (R) is the correct explanation of (A)

Both (A) and (R) are true but (R) is not the correct explanation of (A)

(A) is true but (R) is not true

(A) is not true but (R) is true

$K, Rb$ and $Cs$ form superoxides. The stability

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Concepts Used:

Group 1 Elements

Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkali metals are characterized by one s-electron in the valence shell of their atoms.

Alkali metals have a corresponding [Noble gas] ns¹ electronic configuration. They occupy the first column of the periodic table. Alkali elements are:

Lithium(Li)
Sodium(Na)
Potassium (K)
Rubidium (Ru)
Cesium (Cs)
Francium (Fr)

They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.

Electronic Configuration:

Alkali metals have one electron in their valence shell.
The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).

This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.

$K, Rb$ and $Cs$ form superoxides. The stability of the superoxides increases from '$K$' to '$Cs$' due to decrease in lattice energy. The correct answer is

The Correct Option is A

Solution and Explanation

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Concepts Used:

Group 1 Elements

Electronic Configuration:

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