In acid medium, dichromate oxidizes sulphite to sulphate. In this redox reaction, the oxidation state of sulphur changes from \(x\) to \(y\). What is the value of \(x + y\)?
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Always assign oxidation states using standard rules: Oxygen is typically -2, and the sum of oxidation numbers equals the charge on the ion. For redox questions, compare oxidation states to track electron transfer.
Step 1: Identify oxidation states of sulphur in sulphite and sulphate.
In sulphite (SO\(_3^{2-}\)):
\[
\text{Oxidation state of S} = x \Rightarrow x + 3(-2) = -2 \Rightarrow x = +4
\]
In sulphate (SO\(_4^{2-}\)):
\[
\text{Oxidation state of S} = y \Rightarrow y + 4(-2) = -2 \Rightarrow y = +6
\]
Step 2: Calculate \(x + y\)
\[
x + y = 4 + 6 = 10
\]