Question:

In a tangent galvanometer, a current of 1A produces a deflection of 30?. The current required to produce a deflection of 60? is

Updated On: Apr 15, 2024
  • 3A
  • 2A
  • 4A
  • 1A
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The Correct Option is A

Solution and Explanation

Current in tangent galvanometer
$I=\frac{H}{G}tan\theta$
Where G = galvanometer constant
H= earth's horizontal field = constant
$\therefore \frac{I_1}{I_2}=\frac{tan\theta_1}{tan\theta_2} \Rightarrow \frac{I}{I_2}=\frac{tan30^{\circ}}{tan60^{\circ}}$
$\Rightarrow I_2 = \frac{tan60^{\circ}}{tan30^{\circ}}=\frac{1.7321}{0.5774}=2.999 \dot{A}$
$\Rightarrow I_2=3A$
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Concepts Used:

Electrical Instruments

There are various electrical instruments used to measure current, power, voltage, etc.  Some of them are briefly explained below:

Moving Coil Galvanometer

  • It is an electromagnetic device which measures small values of current.
  • Its working principle is that whenever a current loop is placed in a magnetic field, it experiences a certain torque. The value of that torque can be modified by modifying the current in the loop.
  • For a current carrying loop having N turns, and cross sectional area A, carrying current i, whenever it is placed in and along the direction of an external magnetic field B, it experiences a torque given by:

ԏ = NiAB

moving coil galvanometer