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An ammeter reads upto $1A$. Its internal resistance is $0.81\, \Omega$ . To increase the range to $10\, A$, the value of the required shunt is
An ammeter reads upto $1A$. Its internal resistance is $0.81\, \Omega$ . To increase the range to $10\, A$, the value of the required shunt is
Updated On: Apr 26, 2024
- $0.09\, \Omega$
- $0.03\, \Omega$
- $0.3\, \Omega$
- $0.9\, \Omega$
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The Correct Option is A
Solution and Explanation
Shunt $S=\frac{GI}{I-I_{g}}$
$=\frac{0.81\times1}{10-1}=\frac{0.81}{9}\Omega=0.09\,\Omega$
$=\frac{0.81\times1}{10-1}=\frac{0.81}{9}\Omega=0.09\,\Omega$
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