In a face centred cubic lattice, atoms of $A$ form the comer points and atoms of $B$ form the face centred points. If two atoms of $A$ are missing from the comer points, the formula of the ionic compound is :
- $AB_3$
- $AB_4$
- $A_2B_5$
- $AB_2$
The Correct Option is B
Solution and Explanation
$\therefore$ Atoms at comer $\left(A\right)=6\times\frac{1}{8}=\frac{3}{4}$
Atoms at face centre $\left(B\right)=6\times \frac{1}{2}=3$
$\therefore A_{3/4}B_{3}i.e., AB_{4}$
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Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions.
Types of Solids:
Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;
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