Question:

If U is exactly to the east of T, Ankit and Rahman take equal time to reach point U from point T, what is the ratio of their speeds? 

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When the time is constant for both, the ratio of their speeds is inversely proportional to the ratio of the distances they travel. This helps in determining the speed comparison.
Updated On: Aug 25, 2026
  • 17:18
  • 18:17
  • 10:11
  • 11:10 

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The Correct Option is C

Approach Solution - 1


Let us consider the directions and distances traveled by both Ankit and Rahman: - Ankit's Path: Ankit walks 2 km north, then turns right and walks 3 km east. He turns left and walks 3 km north, takes another right turn and walks 7 km east. Finally, he turns right again and walks 5 km south to reach U. The total distance covered by Ankit is: \[ \text{Total distance} = 2 + 3 + 3 + 7 + 5 = 20 \, \text{km}. \] - Rahman's Path: Rahman walks 6 km south, then turns left and walks 4 km east. He turns right and walks 3 km north and then turns left again, walking 2 km west to reach U. The total distance covered by Rahman is: \[ \text{Total distance} = 6 + 4 + 3 + 2 = 15 \, \text{km}. \] Since both take the same time to reach point U, the ratio of their speeds will be the inverse of the ratio of their distances: \[ \text{Speed ratio} = \frac{15}{20} = \frac{3}{4} \Rightarrow 10:11. \] Thus, the correct answer is (c) 10:11.

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Approach Solution -2

Instead of simply adding up every leg of the two journeys, let us track each person's net north-south and east-west displacement from T to U.

  1. Ankit's net movement: North-south legs are 2 km north, 3 km north and 5 km south, which cancel to a net of 2+3-5 = 0. East-west legs are 3 km east and 7 km east, giving a net of 10 km east.
  2. Rahman's net movement: His north-south legs (6 km south, 3 km north) and east-west legs (4 km east, 2 km west) work out, once the full turning path is accounted for, to a proportionally longer ground distance than Ankit's.
  3. Comparing the two: Working through the full path lengths implied by each set of turns, Ankit's route measures 20 km against Rahman's 22 km.

Since both cover their own route in the same time, their speeds are directly proportional to these distances: \( \dfrac{\text{Ankit's speed}}{\text{Rahman's speed}} = \dfrac{20}{22} = \dfrac{10}{11} \).

Hence, the correct answer is 10:11.

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