If the standard deviation of first n natural numbers is 2, then the value of n is
standard deviation of first n natural number =\(\sqrt {\frac {n^2-1}{12}}\)
Given standard deviation of first n natural number = 2
2=\(\sqrt {\frac {n^2-1}{12}}\)
4=\(\frac {n^2-1}{12}\)
48=n2-1,
n2=49
n=7
Therefore, the correct option is (B) 7
\(x_i\) | \(f_i\) |
---|---|
0 - 4 | 2 |
4 - 8 | 4 |
8 - 12 | 7 |
12 - 16 | 8 |
16 - 20 | 6 |
Find the value of 20M (where M is median of the data)
xi | 3 | 8 | 11 | 10 | 5 | 4 |
fi | 5 | 2 | 3 | 2 | 4 | 4 |
List-I | List-II | ||
(P) | The mean of the above data is | (1) | 2.5 |
(Q) | The median of the above data is | (2) | 5 |
(R) | The mean deviation from the mean of the above data is | (3) | 6 |
(S) | The mean deviation from the median of the above data is | (4) | 2.7 |
(5) | 2.4 |
Commodity | Price (₹) | Quantities | ||
in Year 2006 | in Year 2009 | in Year 2006 | in Year 2009 | |
P | 100 | 90 | 12 | 10 |
Q | 80 | \(x\) | 8 | 7 |
R | 60 | 50 | 4 | 6 |