Question:

If the collision diameter of \(H_2\) gas is 'x' m and the collision frequency is \(Z_{H_2}\). what will be the collision frequency of \(O_2\), gas (\(Z_{O_2}\)) if its collision diameter is ‘2x’?

Updated On: Mar 18, 2024
  • \(Z_{H_2}=Z_{O_2}\)
  • \(Z_{H_2}=2Z_{O_2}\)
  • \(Z_{H_2}=4Z_{O_2}\)
  • \(2Z_{H_2}=Z_{O_2}\)
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The Correct Option is A

Solution and Explanation

The correct answer is (A) : \(Z_{H_2}=Z_{O_2}\)
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