Question

If Suraj's salary is 40% less than that of Dheeraj, then how much percent is Dheeraj's salary more than that of Suraj?

• A. $56\frac{2}{3}\%$
• B. $66\frac{4}{5}\%$
• C. $66\frac{2}{3}\%$
• D. $33\frac{2}{3}\%$

Hint:

General formula: If $A$ is $R\%$ less than $B$, then $B$ is more than $A$ by: \[ \left(\frac{R}{100 - R}\right) \times 100 \] Here: $\frac{40}{60} \times 100 = 66.66\%$.

Answer 1

The Correct Option is C

Concept: This is a base-comparison percentage problem. When comparing $A$ to $B$, the "than" object is the denominator (the base). If we change the "than" object, the base changes, which changes the percentage.

Step 1: Assign a value to the base.
Let Dheeraj's salary be ₹100.
Since Suraj's salary is 40% less: Suraj's salary $= 100 - (40\% \text{ of } 100) = 100 - 40 = ₹60$.

Step 2: Calculate the percentage difference with Suraj as the base.
Difference between salaries $= 100 - 60 = ₹40$. Now, we want to find how much Dheeraj is more *than* Suraj (Base = 60). \[ \text{Percentage More} = \left(\frac{\text{Difference}}{\text{Suraj's Salary}}\right) \times 100 \] \[ \text{Percentage More} = \left(\frac{40}{60}\right) \times 100 = \frac{2}{3} \times 100 = 66\frac{2}{3}\% \]