Question:

If distance between earth and sun become four times then time period becomes

Updated On: Apr 29, 2024
  • 4 times
  • 8 times
  • 1/4 times
  • 1/8 times
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The Correct Option is B

Solution and Explanation

According to Kepler's third law (law of periods),
$T^{2} \propto R^{3}$
where $T$ is time taken by the planet to go once around the sun $R$ is semimajor axis (distance) of the elliptical orbit.
$=T^{2} \propto k R^{3}$
(where $k$ is constant of proportionality)
When $R$ becomes $4$ times let time period be $T$'.
$=T^{2}=k(4 R)^{3}$
$=\frac{T^{2}}{T^{2}}=\frac{1}{64}$
or $\frac{T}{T'}=\frac{1}{8}$
or $T'=8 T$
So, time period becomes $8$ times of previous value.
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].