To determine the moles of oxygen required for the complete combustion of 1 mole of propane (C\(_3\)H\(_8\)), we must first write the balanced chemical equation for the combustion process. The combustion of propane is represented by:
C\(_3\)H\(_8\) + 5O\(_2\) → 3CO\(_2\) + 4H\(_2\)O
This equation indicates that 1 mole of propane (C\(_3\)H\(_8\)) reacts with 5 moles of oxygen (O\(_2\)) to produce 3 moles of carbon dioxide (CO\(_2\)) and 4 moles of water (H\(_2\)O).
Therefore, 5 moles of oxygen are required to completely combust 1 mole of propane.
| Substance | Moles in Reaction |
|---|---|
| C3H8 | 1 |
| O2 | 5 |
| CO2 | 3 |
| H2O | 4 |
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
X g of nitrobenzene on nitration gave 4.2 g of m-dinitrobenzene. X =_____ g. (nearest integer) [Given : molar mass (in g mol\(^{-1}\)) C : 12, H : 1, O : 16, N : 14]