Question:
Hinsberg reagent is
Hinsberg reagent is
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The Hinsberg test is a useful method for distinguishing between primary, secondary, and tertiary amines using Phthalimide and KOH.
Updated On: Apr 18, 2026
- p-toluene sulphonyl chloride
- Benzene sulphonyl chloride
- Phthalimide and KOH
- Anhydrous ZnCl\(_2\) and conc HCl
- Benzoyl chloride and NaOH
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The Correct Option is C
Solution and Explanation
Step 1: Understanding Hinsberg reagent.
Hinsberg reagent is used in the detection of primary and secondary amines. It reacts with amines to form a sulfonamide derivative. The correct reagent for this test is a combination of Phthalimide and KOH.
Step 2: Explanation of options.
\begin{itemize} \item (A) p-toluene sulphonyl chloride: Incorrect. This is a sulfonyl chloride derivative, but it is not the Hinsberg reagent. \item (B) Benzene sulphonyl chloride: Incorrect. Similar to (A), this compound does not react with amines in the way Hinsberg reagent does. \item (C) Phthalimide and KOH: Correct. Phthalimide and KOH form the Hinsberg reagent, which is used to distinguish primary, secondary, and tertiary amines. \item (D) Anhydrous ZnCl\(_2\) and conc HCl: Incorrect. This combination is used for other reactions such as the Friedel-Crafts alkylation, not for the Hinsberg test. \item (E) Benzoyl chloride and NaOH: Incorrect. This combination is used for other reactions but not for the Hinsberg reagent test. \end{itemize}
Step 3: Conclusion.
Therefore, the correct answer is (C) Phthalimide and KOH, which forms the Hinsberg reagent.
Final Answer: Phthalimide and KOH.
Hinsberg reagent is used in the detection of primary and secondary amines. It reacts with amines to form a sulfonamide derivative. The correct reagent for this test is a combination of Phthalimide and KOH.
Step 2: Explanation of options.
\begin{itemize} \item (A) p-toluene sulphonyl chloride: Incorrect. This is a sulfonyl chloride derivative, but it is not the Hinsberg reagent. \item (B) Benzene sulphonyl chloride: Incorrect. Similar to (A), this compound does not react with amines in the way Hinsberg reagent does. \item (C) Phthalimide and KOH: Correct. Phthalimide and KOH form the Hinsberg reagent, which is used to distinguish primary, secondary, and tertiary amines. \item (D) Anhydrous ZnCl\(_2\) and conc HCl: Incorrect. This combination is used for other reactions such as the Friedel-Crafts alkylation, not for the Hinsberg test. \item (E) Benzoyl chloride and NaOH: Incorrect. This combination is used for other reactions but not for the Hinsberg reagent test. \end{itemize}
Step 3: Conclusion.
Therefore, the correct answer is (C) Phthalimide and KOH, which forms the Hinsberg reagent.
Final Answer: Phthalimide and KOH.
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