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Question:
Glauber salt is
Glauber salt is
Updated On: Jul 28, 2022
- $ MgSO_{4}.H_{2}O $
- $ CuSO_{4}.5H_{2}O $
- $ FeSO_{4}.7H_{2}O $
- $ Na_{2}SO_{4}.10H_{2}O $
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The Correct Option is D
Solution and Explanation
(a) $MgSO _{4} \cdot 7 H _{2} O -$ Epsom salt
(b) $CuSO _{4} \cdot 5 H _{2} O -$ Blue vitrol
(c) $FeSO _{4} \cdot 7 H _{2} O -$ Green vitrol
(d) $Na _{2} SO _{4} \cdot 10 H _{2} O$ - Glauber's salt
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Concepts Used:
Group 1 Elements
Group one of alkali metals is s-block elements with just one electron in their s-orbital. They are are alkali metals. They are named so because of the alkaline nature of the hydroxides and oxides.
Alkali metals are characterized by one s-electron in the valence shell of their atoms.
Alkali metals have a corresponding [Noble gas] ns1 electronic configuration. They occupy the first column of the periodic table. Alkali elements are:
- Lithium(Li)
- Sodium(Na)
- Potassium (K)
- Rubidium (Ru)
- Cesium (Cs)
- Francium (Fr)
They have occupied successive periods from first to seven. Francium is a radioactive element with very low half-life.
Electronic Configuration:
- Alkali metals have one electron in their valence shell.
- The electronic configuration is given by ns1. For example, the electronic configuration of lithium is given by 1ns1 2ns1.
- They tend to lose the outer shell electron to form cations with charge +1 (monovalent ions).
This makes them the most electropositive elements and due to the same reason, they are not found in the pure state.
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