Question:

Given: \(5f (x) 4f(\frac 1x) = x^2 - 4 \) & \(y = 9f(x) × x^2\) If y is strictly increasing, then find interval of \(x\).

Updated On: Sep 21, 2024
  • \((-∞, -\frac {1}{\sqrt 5}]∪(\frac {1}{\sqrt 5},0)\)

  • \((-\frac {1}{\sqrt 5},0)∪(0,\frac {1}{\sqrt 5} )\)

  • \((0,\frac {1}{\sqrt 5})∪(\frac {1}{\sqrt 5} ,∞)\)

  • \((-\sqrt {\frac 25},0)∪(\sqrt {\frac 25},∞)\)

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The Correct Option is D

Solution and Explanation

The correct option is (D): \((-\sqrt {\frac 25},0)∪(\sqrt {\frac 25},∞)\)

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Questions Asked in JEE Main exam

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Concepts Used:

Increasing and Decreasing Functions

Increasing Function:

On an interval I, a function f(x) is said to be increasing, if for any two numbers x and y in I such that x < y, 

⇒ f(x) ≤ f(y)

Decreasing Function:

On an interval I, a function f(x) is said to be decreasing, if for any two numbers x and y in I such that x < y,

⇒ f(x) ≥ f(y)

Strictly Increasing Function:

On an interval I, a function f(x) is said to be strictly increasing, if for any two numbers x and y in I such that x < y,

⇒ f(x) < f(y)

Strictly Decreasing Function:

On an interval I, a function f(x) is said to be strictly decreasing, if for any two numbers x and y in I such that x < y,

⇒ f(x) > f(y)

Graphical Representation of Increasing and Decreasing Functions