From given data (I) 90.8 lit of \(H_2(g)\) at STP (II) 684 gm of sucrose (III) 2 moles of cyclohexane Correct order of total number of atoms will be
- (I) \(>\) (II) \(>\) (III)
- (III) \(>\) (II) \(>\) (I)
- (II) \(>\) (III) \(>\) (I)
- (I) \(>\) (III) \(>\) (II)
The Correct Option is C
Solution and Explanation
Concept: Total number of atoms depends on number of moles of molecules and number of atoms per molecule. \[ \text{Total atoms} = (\text{moles of molecules}) \times (\text{atoms per molecule}) \]
Step 1: Case (I) Hydrogen gas \[ \text{Moles of } H_2 = \frac{90.8}{22.7} = 4 \] Each molecule has 2 atoms. \[ \text{Moles of atoms} = 4 \times 2 = 8 \]
Step 2: Case (II) Sucrose \(C_{12}H_{22}O_{11}\) Molar mass \(= 342\) \[ \text{Moles} = \frac{684}{342} = 2 \] Atoms in one molecule: \[ 12 + 22 + 11 = 45 \] \[ \text{Total atoms} = 45 \times 2 = 90 \]
Step 3: Case (III) Cyclohexane \(C_6H_{12}\) Atoms per molecule: \[ 6 + 12 = 18 \] \[ \text{Total atoms} = 2 \times 18 = 36 \]
Step 4: Compare \[ 90 > 36 > 8 \] Thus, \[ (II) > (III) > (I) \]
Top JEE Main Chemistry Questions
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- At equilibrium the concentrations of and in a sealed vessel at . What will be for the reaction
- Find out the major products from the following reactions
Cobalt chloride when dissolved in water forms pink colored complex $X$ which has octahedral geometry. This solution on treating with cone $HCl$ forms deep blue complex, $\underline{Y}$ which has a $\underline{Z}$ geometry $X, Y$ and $Z$, respectively, are
- The correct order of atomic radii is:
Top JEE Main Physical Chemistry Questions
- Consider the following equilibrium: \[ 2AB \rightleftharpoons A_2 + B_2 \] If equilibrium pressure is \(P\) and degree of dissociation is \(\alpha\), then \(K_p\) is
- Consider the following electrochemical cell \[ Zn | Zn^{2+}(aq) \, || \, Ag^{+}(aq) | Ag \] \[ [Zn^{2+}] = 1\,M \] The \(E_{cell\) was found to be \(1.6\,V\). The value of \(\log[Ag^+]\) is \[ E^\circ_{Zn^{2+}/Zn} = -0.76\,V , \qquad E^\circ_{Ag^+/Ag} = +0.80\,V \]
- For a first order reaction : \[ \text{A(g)} \rightarrow \text{B(g)} + \text{C(g)} \] If initial pressure is \( P_0 \) and total pressure at time \( t \) is \( P_t \), then the expression of rate constant \( K \) is:
- On heating \(2.76\,\text{g}\) of \( \text{Ag}_2\text{CO}_3 (s) \), some solid residue is left behind. Determine the mass of residue left.
- Determine mole fraction of water in an aqueous solution of urea having \(10\%\) w/w urea.
Top JEE Main Questions
- Two masses $m$ and $\frac{m}{2}$ are connected at the two ends of a massless rigid rod of length $l$. The rod is suspended by a thin wire of torsional constant $k$ at the centre of mass of the rod-mass system(see figure). Because of torsional constant $k$, the restoring torque is $\tau =k\theta$ for angular displacement $\theta$. If the rod is rota ted by $\theta_0$ and released, the tension in it when it passes through its mean position will be:
What will be the equilibrium constant of the given reaction carried out in a \(5 \,L\) vessel and having equilibrium amounts of \(A_2\) and \(A\) as \(0.5\) mole and \(2 \times 10^{-6}\) mole respectively?
The reaction : \(A_2 \rightleftharpoons 2A\)- The value of is
- The number of terms of an is even. The sum of the odd terms is and of the even terms is . The last term exceeds the first by . Then the number of terms in the series is ______.
A black body is at a temperature of 2880 K. The energy of radiation emitted by this body with wavelength between 499 nm and 500 nm is U1, between 999 nm and 1000 nm is U2 and between 1499 nm and 1500 nm is U3. The Wien's constant, b = 2.88×106 nm-K. Then,